bigboikv2 bigboikv2

13-06-2020
Chemistry

contestada

If 4520 kJ of heat is needed to boil a sample of water, what is the mass of the sample of water (ΔHvaporiztion = 2260kJ/kg)?

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barakaodoyo5 barakaodoyo5

17-06-2020

Answer:2kg

Explanation:heat gained=heat lost

mass x 2260=4520

4530÷2260

And=2kg

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