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There is a lever. The fulcrum is 1 m from the left end, and 3 m from the right end. A block of 60 N is hung to the left end. To keep the lever in horizontal, how much force is needed on the right end?

Respuesta :

Answer:

F = 20 N

Explanation:

It is given that,

The fulcrum is 1 m from the left end, and 3 m from the right end. A block of 60 N is hung to the left end. We need to find the force needed on the right end such that it balances it. The torque acting on the left end is equal to the torque acting on another side. Let F is the force needed on the right end. So,

[tex]60\times 1=F\times 3\\\\F=20\ N[/tex]

So, the force of 20 N is needed on the right end.

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