Answer:
In radical from 169/50 , 177/200
Step-by-step explanation:
Given:
[tex]2x^2=5x+6\\\\2x^2-5x-6=0\\\\Where, a=2 , b=-5 , c=-6[/tex]
Find:
Value of [tex]x[/tex]
Computation:
Using quadratic formula:
[tex]\frac{-b\±\sqrt{b^2-4ac} }{2a}\\\\By\ putting\ all\ value\\\\ \frac{-(-5)\±\sqrt{(-5)^2-4(2)(-6)} }{2(2)}\\\\ \frac{5\±\sqrt{25+48} }{4}\\\\ \frac{5\±8.54 }{4}\\\\\frac{5+8.54 }{4},\frac{5-8.54 }{4} \\\\3.38 , 0.885[/tex]
Value of [tex]x[/tex] 3.38 , 0.885
In radical from 169/50 , 177/200
