Respuesta :
Answer:
The player's height is 3.02 standard deviations above the mean.
Step-by-step explanation:
Consider a random variable X following a Normal distribution with parameter μ and σ.
The procedure of standardization transforms individual scores to standard scores for which we know the percentiles (if the data are normally distributed). Â
Standardization does this by transforming individual scores from different normal distributions to a common normal distribution with a known mean, standard deviation, and percentiles.
A standardized score is the number of standard deviations an observation or data point is above or below the mean.
The standard score of the random variable X is:
[tex]Z=\frac{X-\mu}{\sigma}[/tex]
These standard scores are also known as z-scores and they follow a Standard normal distribution, i.e. N (0, 1).
It is provided that the height of a successful basketball player is 196 cm.
The standard value of this height is, z = 3.02.
The z-score of 3.02 implies that the player's height is 3.02 standard deviations above the mean.
The player's height is 3.02 standard deviations above the mean.
- The calculation is as follows:
The standard scores are also called as z-scores and they follow a Standard normal distribution, i.e. N (0, 1).
Since it is given that the height of a successful basketball player is 196 cm.
Now
The standard value of this height is, z = 3.02.
So here
The z-score of 3.02 represent that the player's height is 3.02 standard deviations above the mean.
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