Answer:
The products are: KCl03 and H20.
Explanation:
The reaction between HC03 (chloric acid) and KOH (potassium hydroxide) is:
HC03 + KOH ----> KCl03 (KCl03 and H20) + H20 (water)
The reaction is of the double displacement type (in this case parts of the reagents are exchanged, producing two generating new compounds).
