Respuesta :

caylus
Hello,

x<y<z (1)
xy=6b (2)
yz=8b (3)
xz=175 (4)

(2)/(3)==>x/z=6/8==>x=3z/4 (5)
(4) and (5)==>3z/4*z=175==>z²=700/3==>z=√(700/3) (6)
(5) and (6)==>x=3/4*√(700/3) (7)

(1) and (7) ==>3/4*√(700/3)<y<√(700/3) (8)
(8)*z==>3/4*√(700/3)*√(700/3)<yz<√(700/3)*√(700/3)
==>175<yz<700/3
 




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