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A passenger on a moving train walks at a speed of 1.40 m/s due north relative to the train. The train is traveling at 3.5 m/s due east relative to the ground. What are the magnitude and direction of the velocity of the passenger relative to the ground

Respuesta :

Answer:

v= 4.9 m/s in east direction ( or  v=4.9 m/s * i )

Explanation:

Since the passenger moves along the train ( in the north direction relative to the train) then if the train is traveling east relative to the ground , the passenger will also travel to the east relative to the ground .  

Then the magnitude of the velocity will be

v= 1.40 m/S + 3.5 m/s = 4.9 m/s

v= 4.9 m/s

and the direction will be east ( if the x axis represents east direction and y-axis the north direction , then the velocity vector will be  v=4.9 m/s * i )

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