contestada

Two horizontal forces act on a 2.0kg chopping block that canslide over a frictionless kitchen counter, which lies in an xyplane. One force is F1= (3.0N)i + (4.0N)j. Find the acceleration ofthe chopp;ing block in unot-vector notation when the other forceis:
a) F2= (-3.0N)i + (-4.0N)j
b) F2= (-3.0N)i + (4.0N)j
c) F2=(3.0N)i + (-4.0N)j

Respuesta :

Explanation:

Given that,

Mass of the block, m = 2 kg

(a) Force, [tex]F=(3i+4j)\ N[/tex]

Acceleration,

[tex]a=\dfrac{F}{m}[/tex]

[tex]a=\dfrac{1}{2}(3i+4j)\ m/s^2[/tex]

(b) [tex]F=(-3i-4j)\ N[/tex]

Acceleration,

[tex]a=\dfrac{1}{2}(-3i-4j)\ m/s^2[/tex]

(c) [tex]F=(-3i+4j)\ N[/tex]

Acceleration,

[tex]a=\dfrac{1}{2}(-3i+4j)\ m/s^2[/tex]

(d) [tex]F=(3i-4j)\ N[/tex]

[tex]a=\dfrac{1}{2}(3i-4j)\ m/s^2[/tex]

Hence, this is the required solution.                                                

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