via16
via16 via16
  • 16-06-2016
  • Mathematics
contestada

Expand: (2n + 5k)2 polynomial identeties

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sleepyjess
sleepyjess sleepyjess
  • 16-06-2016
(2n + 5k)^2 = (2n + 5k)(2n + 5k)
Here we need to use FOIL
First - 2n * 2n = 4n^2
Outside - 2n * 5k = 10nk
Inside - 5k * 2n = 10nk
Last - 5k * 5k = 25k^2

That gives us 4n^2 + 10nk + 10nk + 25k^2, we can combine 10nk + 10nk to give 20nk, and a final equaion of 4n^2 + 20nk + 25k^2
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IloveDolphins
IloveDolphins IloveDolphins
  • 16-06-2016
(x2 + y2)2 = (x2 – y2)2 + (2xy)2 is true for any x and y. That is an example.... so in your case i think it would be 
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