bigbrainman121
bigbrainman121 bigbrainman121
  • 12-12-2019
  • Mathematics
contestada

Give the equation of the circle centered at the origin and passing through the point (0,-8)

Respuesta :

joseaaronlara
joseaaronlara joseaaronlara
  • 12-12-2019

Answer:

The answer to your question is x ² + y² = 64

Step-by-step explanation:

Process

1.- Find the length of the radius

C (0, 0)

P (0, -8)

d = [tex]\sqrt{(x2 - x1)^{2}+ (y2 - y1)^{2}  }[/tex]

d = [tex]\sqrt{(0- 0)^{2}+ (-8 - 0)^{2}  }[/tex]

d = [tex]\sqrt{64}[/tex]

d = 8

2.- Find the equation of the circle

    [tex](x - h)^{2} + (y - k)^{2} = r^{2} \\[/tex]

h = 0   and k = 0

    [tex](x - 0)^{2} + (y - 0)^{2} = 8^{2}[/tex]

            x² + y² = 64      

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