Answer:
[tex]B= 1.14 X 10^{-7} Tesla[/tex]
Explanation:
B at point 7.0 cm radially outward is to find out?
Now for field strength in case of parallel plates in given as
[tex]B=\frac{I\mu}{2r\pi}[/tex]
[tex]B=\frac{4\pi X 10^{-7} \frac{Tm}{A}X40 X10^{-3} \frac{C}{s}}{2X0.07mX\pi}[/tex]
[tex]B= 1.14 X 10^{-7} Tesla[/tex]
For the second part as Capacitor is fully charged no more flow of current could take place hence
I= Current =o
so B = 0
