Answer:
[tex]q=+8.34*10^{-7}C}[/tex]
Explanation:
The potential V due to a charge q, at a distance r, is:
[tex]V=k\frac{q}{r}[/tex]
k=8.99×109 N·m^2/C^2 :Coulomb constant
We replace the values in order to find q:
[tex]q=\frac{V*r}{k}=\frac{500*15}{8.99*10^{9}}=8.34*10^{-7}C[/tex]
