Answer:
11.125°
Explanation:
Given:
Radius of bend, R = 100 m
Speed around the bend = 50 Km/hr = [tex]\frac{5}{18}\times50[/tex] = 13.89 m/s
Now,
We have the relation
[tex]\tan\theta=\frac{v^2}{gR}[/tex]
where,
θ = angle of banking
g is the acceleration due to gravity
on substituting the respective values, we get
[tex]\tan\theta=\frac{13.89^2}{9.81\times100}[/tex]
or
[tex]\tan\theta=0.1966[/tex]
or
θ = 11.125°
