the diagonals of a rhombus bisect the angles.
if angle 2 is 48, angle 4 is also 48. therefore, by alternating interior angles, angles 9 and 7 are also 48. This means m<MOH = 96.
if angle 7 is 61, angle 9 is 61 as well. this means m<MOH is 122. therefore m<RHO = 180 - m<MOH. this means m<RHO = 58.
I'm not sure I understand the context of 5. how are do they expect you to solve for x? you could solve for it in terms of m<3, which would mean x = (m<3 + 6)/8.
