Answer: [tex]v_{rms}=13.03ms^{-1}[/tex]
Explanation: Using ideal gas equation:
PV = nRT
[tex]T=\frac{PV}{nR}[/tex]
P= pressure = 3.5 atm
V= volume =[tex]8.5m^3=8500L[/tex]
n = no of moles = 1900
R= gas constant =0.0821 Latm\molK
[tex]T=\frac{3.5\times 8500}{1900\times 0.0821}=190.7K[/tex]
[tex]v_{rms}=\sqrt{\frac{3RT}{M}}[/tex]
R= gas constant = 8.314 J/Kmol
T= temperature = 190.7 K
M= molecular mass of nitrogen = 28 g/mol
[tex]v_{rms}=\sqrt {\frac {3\times 8.314\times 190.7}{28}}[/tex]
[tex]v_{rms}=13.03ms^{-1}[/tex]
