y = 2x^2 - 12x + 46
Compare your equation with the standard form of the equation:
y = ax^2 + bx + c
For your equation, a = 2, b = -12, c = 46.
The vertex has x-coordinate -b/(2a).
The x-coordinate of the vertex is: -(-12)/(2 * 2) = 12/4 = 3
Now we plug in x = 3 into the function to find the y-coordinate of the vertex.
y = 2(3^2) - 12(3) + 46
y = 2(9) - 36 + 46
y = 18 - 36 + 46
y = 28
The vertex is (3, 28)
