At least how many grams of copper must be alloyed with 387 g of pure silver to produce an alloy that is no more than 90% pure silver

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jrmaxwell1999 jrmaxwell1999 · Answer 1 · 2018-11-14T00:14:04+01:00

Let c = grams of copper to be added

(grams of silver) / (grams of copper and silver) < = .90

387+%2F+%28c+%2B+387%29+%3C=+.9

387+%3C=+.9%28c+%2B+387%29

387+%3C=+.9c+%2B+348.3

.9c+%3E=+387+-+348.3

.9c+%3E=+38.7

c+%3E=+43g

At least 43 grams of copper must be added

check:

387+%2F+%28c+%2B+387%29+%3C=+.9

387+%2F+%2843+%2B+387%29+%3C=+.9

387+%2F+430+%3C=+.9

.9+%3C=+.9

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