HarveytheHamster
HarveytheHamster HarveytheHamster
  • 03-03-2016
  • Chemistry
contestada

What is the molarity of a CaCl2 solution containing 330 grams of CaCl2 in 1 liter of solution?

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Willchemistry
Willchemistry Willchemistry
  • 04-03-2016
Molar mass CaCl₂ = 110.98 g/mol

number of moles :

n = m / molar mass

n = 330 / 110.98

n =2,9735 moles

Molarity ( M ) = moles solute / liters solution

M = 2.9735 / 1

M = 2.9735 mol/L⁻¹

hope this helps!
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