Uzii
Uzii
15-06-2018
Mathematics
contestada
i need help with question 4. a)
Respuesta :
jdoe0001
jdoe0001
15-06-2018
[tex]\bf 4(2x-1)^2=36\implies (2x-1)^2=\cfrac{36}{4}\implies (2x-1)^2=9 \\\\\\ \sqrt{(2x-1)^2}=\sqrt{9}\implies 2x-1=\pm 3\implies 2x = \pm 3 +1 \\\\\\ x=\cfrac{\pm 3 +1}{2}\implies x= \begin{cases} \cfrac{4}{2}\implies &2\\\\ \cfrac{-2}{2}\implies &-1 \end{cases}[/tex]
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