see the picture attached to better understand the problem we know that 90°+∠BAC=180°------> by supplementary angles ∠BAC=90° 125°+∠ABC=180° -----> by supplementary angles ∠ABC=55° ∠BAC+∠ABC+p=180----> sum of the internal angles of a triangle is 180 degrees p=180-90-55-----> p=35°
