Answer:
a² + b² = 68
a3 + b3 = 520
Step-by-step explanation:
Given :
a + b = 10 (1)
ab = 16 (2)
A. Find a² + b²
(a + b)² = a² + 2ab + b² (3)
Substitutite the values of (1) and (2) into (3)
(10)² = a² + 2(16) + b²
100 = a² + 32 + b²
Subtract 32 from both sides
100 - 32 = a² + b²
a² + b² = 68
B. a^3 + b^3
(a + b)^3 = a^3 + b^3 + 3ab(a + b)
(10)^3 = a^3 + b^3 + 3*16(10)
1000 = a^3 + b^3 + 480
a^3 + b^3 = 1000 - 480
a3 + b3 = 520
