kosi2243
kosi2243 kosi2243
  • 13-08-2016
  • Mathematics
contestada

Diffrentiate Acos(ax)

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caylus
caylus caylus
  • 13-08-2016
Hello,

It is an immediate.

(Arccos ax)'=[tex] \dfrac{-a}{ \sqrt{1-(ax)^2} } [/tex] 0<Arccos (ax) <π

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